# How to calculate Quantity of Cement, Sand & water In Mortar of 1:6

### Quantity of Mortar:-

Volume of mortar= 1 m³
Mix Ratio –>1:6
Dry volume of mortar = Wet volume x 1.33
Dry Volume = 1.0 m³ x 1.33 = 1.33 m³

### Quantity of cement:-

Quantity of Cement = (Dry Volume of mortar x Cement ratio) / (Sum of the ratio)
∴Quantity of cement = (1.33 x 1) /(1+6)=0.19 m³
Density of Cement = 1440 kg/m³
∴ Weight of Cement = 1440 kg/m³ x 0.19 m³ = 273.6 Kg
1 bag of cement contains 50 kg of cement
∴ Number of bags = 273.6 Kg/50 = 5.472 No’s

### Quantity of Sand:-

Quantity of Cement = (Dry Volume of mortar x Cement ratio) / (Sum of the ratio)
∴Quantity of cement = (1.33 x 1) /(1+6)=0.19 m³
Density of Cement = 1440 kg/m³
∴ Weight of Cement = 1440 kg/m³ x 0.19 m³ = 273.6 Kg
1 bag of cement contains 50 kg of cement
∴ Number of bags = 273.6 Kg/50 = 5.472 No’s

### Quantity of water:-

Water cement ratio = weight of water/weight of cement
W/C–>0.50
weight of water = (weight of cement)x(w/c ratio)
∴ Weight of water = 273.6 Kg x 0.5 =136.8 kg (Litre)
Watch the video given in the link below, for better understanding and detailed explanation

How to calculate Cement Sand & Water in Mortar (1:6 &1:3)

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