**Q:- Calculate the cutting length of the stirrups given in fig 1. Clear cover of beam is 25 mm & Diameter of stirrup is 8 mm**

**Ans:-**

Given data:

Clear cover = 25 mm

Depth of beam = 450 mm

Width of beam = 300 mm

Diameter of stirrup =8 mm

**Cutting length of stirrup = 2a+2b + (2 x Hook length) – Bend deduction**

Where,

a= Width of beam – (2 x clear cover) – ( 2 x Half of diameter of bar)

b= Depth of beam – (2 x clear cover) – ( 2 x Half of diameter of bar)

Therefore,

a= 300 – (2 x 25) – (2 x 4) = 242 mm

b= 450 – (2 x 25) – (2 x 4) = 392 mm

Length of hook (Development length) = **10 d** = 10×8 = 80 mm

**Bend deductions: **

90 degree bent –> 3 no’s

For **90 degree bend**, length reinforced bar increase by **2 d**

i.e., Bend length = 3 x (2×8) = 3×16 = 48 mm

135 degree bent –> 2 no’s

For **135 degree bend,** length reinforced bar increase by **3d**

i.e., Bend length = 2 x (3×8) = 2 x 24 = 48 mm

**∴ Cutting length of stirrup = **(2×242) + (2×392) + (2×80) – (48+48) = 1428 – 96 **= 1332 mm**

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