**Quantity of Bricks:-**

**Assuming:-**

•Brick size = **9”x4.5”x3” **

•Thickness of wall = **9”**

•Thickness of mortar = 0.39**”**

•Brick size with mortar= (9+0.39)x(4.5+0.39)x(3+0.39) = 9.39”x4.89”x3.39” •

** No. of bricks = Volume of Brickwork/ Volume of 1 Brick with mortar**

Volume of 1 Brick = (9/12)x(4.5/12)x(3/12)= 0.75’x0.375’x0.25’ = 0.070 CFT

Volume of 1 Brick with mortar = 0.783’x0.408’x0.283’=0.090 CFT.

Volume of Brickwork = 10’ x 6’ x 0.75’ = 45 Cubic Foot (CFT)

**No. of bricks = Volume of Brickwork/ Volume of 1 Brick with Mortar**

∴** **No. of bricks **= **45 CFT/ 0.090 CFT

**= 500 No’s**

*Brick wastage–>** 5 to 10 %*

Consider 10% brick wastage,

∴ No. of bricks= 500 + (500 x 0.1)

**= 550 No’s**

**Quantity of cement:-**

**Quantity of mortar = Quantity of brickwork – Volume of Bricks**

Volume of bricks =0.070 CFT x 500 No’s = 35 CFT

Quantity of mortar = 45 – 35

= 10 CFT

**Mix Ratio –> 1:5**

**Dry volume of mortar = Wet volume x (1+0.33) ***(33% of volume)*

Dry Volume of mortar= 10 x 1.33 = 13.3 CFT

Consider 5% wastage of mortar.

Dry volume of mortar = 13.3 + (13.3 x 0.05) = 13.3+0.665 = 13.965 ≊ 14 CFT

**Quantity of Cement = {(Dry Volume of mortar x Cement ratio) / (Sum of the ratio)}**

∴Quantity of cement = (14 x 1) /(1+5)=2.333 CFT

**Density of Cement = 1440 kg/m³ **

*1 m³=35.3147 Cubic Feet (CFT)*

∴ Quantity of Cement = 2.333/35.3147 = **0.066 m³**

∴ Weight of Cement = 1440 x 0.066 = 95.04 Kg

**1 bag of cement contains 50 kg of cement**

∴ Number of bags = 95.04 Kg / 50 kg = **1.90 No’s (Say 2 No of bags)**

**Quantity of Sand:-**

**Cement : Sand :: 1:5**

**Quantity of Sand = Quantity of Cement x 5**

∴ Quantity of Sand = 2.333 x 5= **11.665 CFT**

*1 m³=35.3147 Cubic Feet (CFT)*

∴ Quantity of sand = 11.665/35.3147 = **0.330 m³**

*Density of sand = 1600 kg/m³*

∴ Weight of the sand= 0.330 x 1600= **528 kg (0.528 tonnes)**

**From the link below you can find the video for this blog, watch it for a clear understanding & detailed explanation.**